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Question -

Find the 10th term from the end of the A.P. 8, 10, 12, …, 126. (C.B.S.E. 2006)



Answer -

The given A.P. is 8, 10, 12, …, 126
Here first term (a) = 8
Common difference (d) = 10 – 8 = 2
and last tenn (l) = 126
Now nth term from the last is an = l – (n – 1) d
a10 = 126 – (10 – 1) x 2 = 126 – 9 x 2 = 126 – 18 = 108

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