The Total solution for NCERT class 6-12
(i) 4 , 7 p = 4 × 7 × p = 28p
(ii) – 4p × 7p = (-4 × 7 ) × (p × p )= -28p2
(iii) – 4p × 7pq =(-4 × 7 ) (p × pq) = -28p2q
(iv) 4p3 ×– 3p = (4 × -3 ) (p3 ×p ) = -12p4
(v) 4p × 0 = 0