MENU
Question -

निम्नलिखित व्यंजकों के गुणनखण्ड कीजिएजबकि व्यंजकों के प्रत्येक पद में एक उभयनिष्ठ गुणनखण्ड हैं
(i) x(y-z) +4 (y-z)
(ii) 2(5 + b)-7 (5+ b)
(iii) y(a_2 + x) – a_2 = x)
(iv) a(a + 3) -5 (3 + a)



Answer -

(i) x(y-z)+4 (y-z)
हल :
x(y – z) + 4 (y – z)
= (y – z) (x + 4)

(ii) 2(5 + b)-7 (5+ b)
हल :
2(5 + b) -7 (5 + b)
= (5 + b) (2 – y)
=-5(5 + b)

(iii) y(a2 +x) – a2 = x)
हल :
y(a2 + x) – a2 =x)
= (a
2 + x) (y- 1)

(iv) a(a + 3) -5 (3 + a)
हल :
a(a + 3) -5 (3 + a),
= (a + 3) (9 – 5)

 

Comment(S)

Show all Coment

Leave a Comment

×