The Total solution for NCERT class 6-12
(i) 5x2 –25xyहल :5x2 – 25xy= 5x (x – 5y)
(ii) 9a2 –6axहल :9a2 – 6ax= 3a (3a – 2x)
(iii) 36ab – 60 a°beहल :36 a2b – 60 a2bc= 12ab(3a – 5ac)
(iv) 6P+ 8P2-4P3हल :6P +8P2 – 4P3= 2P (3 + 4P – 2P2)
(v) 3a2be + 6ab2c +9abc2हलः3a2bc + 6ab2c +9abc2= 3abc (a + 2b = 3c)