Question -
Answer -
Let smaller number = x
Then larger number = 2x – 5
According to the condition,
(2x – 5)2 – x2 = 88
=> 4x2 – 20x + 25 – x2 – 88 = 0
=> 3x2 – 20x – 63 = 0
=> 3x2 – 27x + 7x – 63 = 0
=> 3x (x – 9) + 7 (x – 9) = 0
=> (x – 9) (3x + 7) = 0
Either x – 9 = 0, then x = 9
or 3x + 7 = 0, then x = −73 which is not possible
Smaller number = 9
and greater number = 2x – 5 = 2 x 9 – 5 = 18 – 5 = 13
Hence numbers are 13, 9