The Total solution for NCERT class 6-12
(i) тИЖABD тЙЕ тИЖBAC(ii) BD = AC(iii) тИаABD = тИа BAC
In quadrilateral ACBD, we have AD = BC and тИа DAB = тИа CBA
(i) In тИЖ ABC and тИЖ BAC,AD = BC (Given)тИаDAB = тИаCBA (Given)AB = AB (Common)тИ┤ тИЖ ABD тЙЕ тИЖBAC (By SAS congruence)
(ii) Since тИЖABD тЙЕ тИЖBACтЗТ BD =AC [By C.P.C.T.]
(iii) Since тИЖABD тЙЕ тИЖBACтЗТ тИаABD = тИаBAC [By C.P.C.T.]