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Question -

Find the value of p, if the mean of the following distribution is 20.

X

15

17

19

20 + p

23

f

2

3

4

5p

6



Answer -


5p2 +100p + 295 = 20 (15 + 5p)
5p2 +100p + 295 = 300 + 100p
5p2 +100p – 100p = 300 – 295
  5p2 =5   p2 =  5/5  = 1
P= ±1
P = -1 i s not possible
p= 1

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