Question -
Answer -
Let A = (6, -6), B = (3, -7), C = (3, 3) arethe points on a circle.
If O is the centre, then OA = OB = OC (radiiare equal)
If O = (x, y) then
OA =
OB =
OC =
Choose: OA = OB, we have
After simplifying above, we get -6x = 2y – 14….(1)
Similarly: OB = OC
(x – 3)2 + (y + 7)2 =(x – 3)2 + (y – 3)2
(y + 7)2 = (y – 3)2
y2 + 14y + 49 = y2 –6y + 9
20y =-40
or y = -2
Substituting the value of y in equation (1),we get;
-6x = 2y – 14
-6x = -4 – 14 = -18
x = 3
Hence, centre of the circle located at point(3,-2).