The Total solution for NCERT class 6-12
(i) We have
|A| =
= 1(16 – 9) – 3(4 – 3) + 3(3 – 4)
= 7 – 3 – 3
= 1≠ 0
Hence, A – 1 exists
Cofactors of A are
C11 = 7
C21 = – 3
C31 = – 3
C12 = – 1
C22 = 1
C32 = 0
C13 = – 1
C23 = 0
C33 = 1
(ii) We have
= 2(8 – 7) – 3(6 – 3) + 1(21 – 12)
= 2 – 9 + 9
= 2≠ 0
C11 = 1
C21 = 1
C31 = – 1
C12 = – 3
C32 = 1
C13 = 9
C23 = – 5
C33 = – 1