The Total solution for NCERT class 6-12
X2┬атАУ 1 is a factor of ax4┬а+ bx3┬а+cx2┬а+ dx + eтЗТ┬а(x + 1), (x тАУ 1) are the factors of ax4┬а+ bx3┬а+cx2┬а+ dx + eLet f(x) = ax4┬а+ bx3┬а+ cx2┬а+ dx+ eand x + 1 = 0 then x = -1тИ┤┬аf(-1) = a(-1)4┬а+ b(-1)3┬а+ c(-1)2┬а+d(-1) + e= a- b + c- d+ eтИ┤ x + 1is a factor of f(x)тИ┤┬аa-b + c- d+e = 0тЗТ a + c+ e = b + d┬а ┬а ┬а ┬а ┬а ┬а ┬а ┬а┬а┬а(a)