The Total solution for NCERT class 6-12
X2 – 1 is a factor of ax4 + bx3 +cx2 + dx + e⇒ (x + 1), (x – 1) are the factors of ax4 + bx3 +cx2 + dx + eLet f(x) = ax4 + bx3 + cx2 + dx+ eand x + 1 = 0 then x = -1∴ f(-1) = a(-1)4 + b(-1)3 + c(-1)2 +d(-1) + e= a- b + c- d+ e∴ x + 1is a factor of f(x)∴ a-b + c- d+e = 0⇒ a + c+ e = b + d (a)