The Total solution for NCERT class 6-12
The point on the curve x2 =2y which is nearest to the point (0, 5) is
(C) (0, 0) (D) (2, 2)
The given curve is x2 =2y.
Let us denote PA2 by Z. Then,
Z = y2 – 8y +25
Differentiating both sides with respectto y, we get
For maxima or minima, wehave