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Question -

A rectangular sheet of tin 45 cm by 24 cm is to be madeinto a box without top, by cutting off square from each corner and folding upthe flaps. What should be the side of the square to be cut off so that thevolume of the box is the maximum possible?



Answer -

Let the side of the square to be cut offbe x cm. Then, the height of the box is x, thelength is 45 − 2x, and the breadth is 24 − 2x.

Therefore, the volume V(x)of the box is given by,

Now,.

= 18and x = 5

It is not possible to cut off a square ofside 18 cm from each corner of the rectangular sheet. Thus, x cannotbe equal to 18.

x = 5

Now,.
By second derivative test, x =5 is the point of maxima.

Hence, the side of the square to be cut off to make thevolume of the box maximum possible is 5 cm.

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