Question -
Answer -
The equation of the givencurve is
The slope of the tangent to the given curveat any point (x, y) is given by,
The equation of the given line is 4x −2y + 5 = 0.
4x − 2y + 5 = 0 ⇒ 
(which is of the form
∴Slope of the line = 2
Now, the tangent to the given curve isparallel to the line 4x − 2y − 5 = 0 if the slope ofthe tangent is equal to the slope of the line.
∴Equation of the tangent passing through thepoint 
is given by,
Hence, the equation of therequired tangent is