Question -
Answer -
The equation of the given parabola is y2 =4ax.
On differentiating y2 =4ax with respect to x, we have:
∴The slope of the tangent atis
Then, the equation of thetangent atis given by,
y − 2at =
Now, the slope of thenormal atis given by,
Thus, the equation of the normal at (at2, 2at)is given as: