The Total solution for NCERT class 6-12
x4 + x2 + 25⇒ (x2)2 + (5)2 + 2x2 x5 – 2x2 x 5 +x2⇒ (x2)2 + (5)2 + 10x2 –10x2 + x2= (x2)2 + (5)2 + 10x2 –9x2= (x2 + 5)2 – (3x)2 {∵ a2-b2 =(a + b) (a – b)}= (x2 + 5 – 3x) (x2 + 5 + 3x)= (x2 – 3x + 5) (x2 + 3x + 5)