The Total solution for NCERT class 6-12
x3 – 3x2 + 3x + 7 = (x + 1) (ax2 +bx + c)= ax3 + bx2 + cx + ax2 + bx + cx3 – 3x2 + 3x – 7 = ax3 + (b +a)2 + (c + b)x + cComparing the coefficient,a = 1b + a = -3 ⇒ b+1=-3 ⇒ b = -3-1=-4c + b = 3 ⇒ c-4 = 3 ⇒ c= 3 + 4 = 7a + b + c = 1- 4 + 7 = 8- 4 = 4 (a)