The Total solution for NCERT class 6-12
a3 – 3a2b + 3ab2 – b3 +8= (a – b)3 + (2)3= (a – b + 2) [(a -b)2– (a – b) x 2 + (2)2]= (a- b + 2) (a2 + b2 -2ab – 2a + 2b + 4)