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Question -

x3y3+ 1



Answer -

x3y3 + 1 = (xy)3 +(1)3
= (xy + 1) [(xy)2 – xy x 1 + (1)2]
= (xy + 1) (x2y2 – xy + 1)
= (xy + 1) (x2y – xy + 1)

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