The Total solution for NCERT class 6-12
(x + 2)3┬а+ (x тАУ 2)3= (x + 2 + x тАУ 2) [(x + 2)2┬атАУ (x + 2) (x тАУ 2) + (x тАУ 2)2]= 2x [x2┬а+ 4x + 4 тАУ (x2┬а+ 2x тАУ 2x тАУ 4) + x2┬а4x+ 4]= 2x[x2┬а+ 4x + 4- x2-2x + 2x + 4+ x2тАУ 4x+ 4]= 2x[x2┬а+ 12]