The Total solution for NCERT class 6-12
4(x тАУ y)2┬атАУ 12(x тАУ y) (x + y) + 9(x + y)2= [2(x тАУ y)2┬а+ 2 x 2(x тАУ y) x 3(x + y) + [3 (x+y]2┬а┬а ┬а ┬а┬а{тИ╡┬аa2┬а+ b2┬а+2 abc = (a + b)2}= [2(x тАУ y) + 3(x + y)]2= (2x-2y + 3x + 3y)2= (5x + y)2