Question -
Answer -
Given,
Third term, a3 = 16
As we know,
a +(3−1)d =16
a+2d = 16………………………………………. (i)
It is given that, 7th termexceeds the 5th term by 12.
a7 − a5 = 12
[a+(7−1)d]−[a +(5−1)d]= 12
(a+6d)−(a+4d) = 12
2d = 12
d = 6
From equation (i), we get,
a+2(6) = 16
a+12 = 16
a = 4
Therefore, A.P. will be4, 10, 16, 22, …