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Question -

Complete the last column of the table.

S. No.

Equation

Value

Say, whether the equation is satisfied. (Yes/No)

(i)

x + 3 = 0

x = 3

(ii)

x + 3 = 0

x = 0

(iii)

x + 3 = 0

x = -3

(iv)

x – 7 = 1

x = 7

(v)

x – 7 = 1

x = 8

(vi)

5x = 25

x = 0

(vii)

5x = 25

x = 5

(viii)

5x = 25

x = -5

(ix)

(m/3) = 2

m = – 6

(x)

(m/3) = 2

m = 0

(xi)

(m/3) = 2

m = 6



Answer -

(i) x + 3 = 0

LHS = x + 3

By substituting thevalue of x = 3

Then,

LHS = 3 + 3 = 6

By comparing LHS andRHS

LHS ≠ RHS

No, the equation isnot satisfied.

(ii) x + 3 = 0

LHS = x + 3

By substituting thevalue of x = 0

Then,

LHS = 0 + 3 = 3

By comparing LHS andRHS

LHS ≠ RHS

No, the equation isnot satisfied.

(iii) x + 3 = 0

LHS = x + 3

By substituting thevalue of x = – 3

Then,

LHS = – 3 + 3 = 0

By comparing LHS andRHS

LHS = RHS

Yes, the equation issatisfied

(iv) x – 7 = 1

LHS = x – 7

By substituting thevalue of x = 7

Then,

LHS = 7 – 7 = 0

By comparing LHS andRHS

LHS ≠ RHS

No, the equation isnot satisfied

(v) x – 7 = 1

LHS = x – 7

By substituting thevalue of x = 8

Then,

LHS = 8 – 7 = 1

By comparing LHS andRHS

LHS = RHS

Yes, the equation issatisfied.

(vi) 5x = 25

LHS = 5x

By substituting thevalue of x = 0

Then,

LHS = 5 × 0 = 0

By comparing LHS andRHS

LHS ≠ RHS

No, the equation isnot satisfied.

(vii) 5x = 25

LHS = 5x

By substituting thevalue of x = 5

Then,

LHS = 5 × 5 = 25

By comparing LHS andRHS

LHS = RHS

Yes, the equation issatisfied.

(viii) 5x = 25

LHS = 5x

By substituting thevalue of x = -5

Then,

LHS = 5 × (-5) = – 25

By comparing LHS andRHS

LHS ≠ RHS

No, the equation isnot satisfied.

(ix) m/3 = 2

LHS = m/3

By substituting thevalue of m = – 6

Then,

LHS = -6/3 = – 2

By comparing LHS andRHS

LHS ≠ RHS

No, the equation isnot satisfied.

(x) m/3 = 2

LHS = m/3

By substituting thevalue of m = 0

Then,

LHS = 0/3 = 0

By comparing LHS andRHS

LHS ≠ RHS

No, the equation isnot satisfied.

(xi) m/3 = 2

LHS = m/3

By substituting thevalue of m = 6

Then,

LHS = 6/3 = 2

By comparing LHS andRHS

LHS = RHS

Yes, the equation issatisfied.

S. No.

Equation

Value

Say, whether the equation is satisfied. (Yes/No)

(i)

x + 3 = 0

x = 3

No

(ii)

x + 3 = 0

x = 0

No

(iii)

x + 3 = 0

x = -3

Yes

(iv)

x – 7 = 1

x = 7

No

(v)

x – 7 = 1

x = 8

Yes

(vi)

5x = 25

x = 0

No

(vii)

5x = 25

x = 5

Yes

(viii)

5x = 25

x = -5

No

(ix)

(m/3) = 2

m = – 6

No

(x)

(m/3) = 2

m = 0

No

(xi)

(m/3) = 2

m = 6

Yes

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