The Total solution for NCERT class 6-12
(i) (3x + 2y + 2z) (9x2 + 4y2 +4z2 – 6xy – 4yz – 6zx)= (3x + 2y + 2z) [(3x)2 + (2y)2 + (2z)2 –3x x 2y + 2y x 2z + 2z x 3x]= (3x)3 + (2y)3 + (2z)3 –3 x 3x x 2y x 2z= 27x3 + 8y3 + 8Z3 – 36xyz(ii) (4x – 3y + 2z) (16x2 + 9y2 + 4z2 +12xy + 6yz – 8zx)= (4x -3y + 2z) [(4x)2 + (-3y)2 + (2z)2 –4x x (-3y + (3y) x (2z) – (2z x 4x)]= (4x)3 + (-3y)3 + (2z)3 – 3 x4x x (-3y) x (2z)= 64x3 – 27y3 + 8z3 + 72xyz(iii) (2a -3b- 2c) (4a2 + 9b2 + 4c2 +6ab – 6bc + 4ca)= (2a -3b- 2c) [(2a)2 + (3b)2 + (2c)2 –2a x (-3b) – (-3b) x (-2c) – (-2c) x 2a]= (2a)3 + (3b)3 + (-2c)3 -3x 2ax (-3 b) (-2c)= 8a3 – 21b3 -8c3 – 36abc(iv) (3x – 4y + 5z) (9x2 + 16y2 + 25z2 +12xy – 15zx + 20yz)= [3x + (-4y) + 5z] [(3x)2 + (-4y)2 + (5z)2 –3x x (-4y) -(-4y) (5z) – 5z x 3x]= (3x)3 + (-4y)3 + (5z)3 – 3 x3x x (-4y) (5z)= 27x3 – 64y3 + 125z3 + 180xyz