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Question -

If
┬а
Find:
(i) f (1/2)
(ii) f (-2)
(iii) f (1)
(iv) f (тИЪ3)
(v) f (тИЪ-3)



Answer -

(i)┬аf(1/2)

When, 0 тЙд x тЙд 1, f(x) = x

тИ┤f (1/2) = ┬╜

(ii)┬аf(-2)

When, x < 0, f(x) = x2

f (тАУ2) = (тАУ2)2

= 4

тИ┤┬аf(тАУ2) = 4

(iii)┬аf(1)

When, x тЙе 1, f (x) = 1/x

f (1) = 1/1

тИ┤┬аf(1)= 1

(iv)┬аf(тИЪ3)

We have тИЪ3 = 1.732 > 1

When, x тЙе 1, f (x) = 1/x

тИ┤f (тИЪ3) = 1/тИЪ3

(v)┬аf(тИЪ-3)

We know┬атИЪ-3┬аis not a real number and the function f(x) isdefined only when x┬атИИ┬аR.

тИ┤┬аf(тИЪ-3)┬аdoes not exist.

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