Question -
Answer -
(i)┬аf(1/2)
When, 0 тЙд x тЙд 1, f(x) = x
тИ┤f (1/2) = ┬╜
(ii)┬аf(-2)
When, x < 0, f(x) = x2
f (тАУ2) = (тАУ2)2
= 4
тИ┤┬аf(тАУ2) = 4
(iii)┬аf(1)
When, x тЙе 1, f (x) = 1/x
f (1) = 1/1
тИ┤┬аf(1)= 1
(iv)┬аf(тИЪ3)
We have тИЪ3 = 1.732 > 1
When, x тЙе 1, f (x) = 1/x
тИ┤f (тИЪ3) = 1/тИЪ3
(v)┬аf(тИЪ-3)
We know┬атИЪ-3┬аis not a real number and the function f(x) isdefined only when x┬атИИ┬аR.
тИ┤┬аf(тИЪ-3)┬аdoes not exist.