The Total solution for NCERT class 6-12
(i) x + √3y – 4 = 0
x + √3y = 4
The normal form of thegiven line, where p = 2, cos α = 1/2 and sin α = √3/2
∴ p = 2 and α = π/3
(ii) x + y + √2 = 0
-x – y = √2
The normal form of thegiven line, where p = 1, cos α = -1/√2 and sin α = -1/√2
∴ p = 1 and α = 225o