Question -
Answer -
Given:
A (−1, 6), B (−3, −9)and C (5, −8) be the coordinates of the given triangle.
Let us assume: D, E,and F be midpoints of BC, CA and AB, respectively. So, the coordinates of D, Eand F are
Median AD passesthrough A (-1, 6) and D (1, -17/2)
So, by using theformula,
4y – 24 = -29x – 29
29x + 4y + 5 = 0
Similarly, Median BEpasses through B (-3,-9) and E (2,-1)
So, by using theformula,
5y + 45 = 8x + 24
8x – 5y – 21=0
Similarly, Median CFpasses through C (5,-8) and F(-2,-3/2)
So, by using theformula,
-14y – 112 = 13x – 65
13x + 14y + 47 = 0
∴ The equation of linesare: 29x + 4y + 5 = 0, 8x – 5y – 21=0 and 13x + 14y + 47 = 0