Question -
Answer -
Given:
The equation passesthrough (2, 3) and make an angle of 450with the line 3x + y – 5= 0.
We know that theequations of two lines passing through a point x1,y1 and making anangle α with the given line y = mx + c are
Here,
Equation of the givenline is,
3x + y – 5 = 0
y = – 3x + 5
Comparing thisequation with y = mx + c we get, m = – 3
x1 =2, y1 = 3, α = 45∘, m = – 3.
So, the equations ofthe required lines are
x + 2y – 8 = 0 and 2x– y – 1 = 0
∴ The equation of givenline is x + 2y – 8 = 0 and 2x – y – 1 = 0