The Total solution for NCERT class 6-12
Given:
The line: 3x – 5y+ 7 = 0
Comparing ax + by + c= 0 and 3x − 5y + 7 = 0, we get:
a = 3, b= − 5 and c = 7
So, the distance ofthe point (4, 5) from the straight line 3x − 5y + 7 = 0 is
∴ The required distanceis 6/√34