Question -
Answer -
(i) A (4, 8), B (5, 12), C(9, 28)
By using the formula,
The slope of the line= [y2 – y1] / [x2 – x1]
So,
The slope of line AB =[12 – 8] / [5 – 4]
= 4 / 1
The slope of line BC =[28 – 12] / [9 – 5]
= 16 / 4
= 4
The slope of line CA =[8 – 28] / [4 – 9]
= -20 / -5
= 4
Here, AB = BC = CA
∴ The Given points arecollinear.
(ii) A(16, – 18), B(3, –6), C(– 10, 6)
By using the formula,
The slope of the line= [y2 – y1] / [x2 – x1]
So,
The slope of line AB =[-6 – (-18)] / [3 – 16]
= 12 / -13
The slope of line BC =[6 – (-6)] / [-10 – 3]
= 12 / -13
The slope of line CA =[6 – (-18)] / [-10 – 16]
= 12 / -13
= 4
Here, AB = BC = CA
∴ The Given points arecollinear.