The Total solution for NCERT class 6-12
(i) 2 and 8
GM between a and b is√ab
Let a = 2 and b =8
GM = √2×8
= √16
= 4
(ii) a3band ab3
Let a = a3band b = ab3
GM = √(a3b× ab3)
= √a4b4
= a2b2
(iii) –8 and –2
Let a = –2 and b = –8
GM = √(–2×–8)
= √–16
= -4