Question -
Answer -
Let the three numbersbe a/r, a, ar
So, according to thequestion
a/r + a + ar = 39/10 …equation (1)
a/r × a × ar = 1 …equation (2)
From equation (2) weget,
a3 = 1
a = 1
From equation (1) weget,
(a + ar + ar2)/r= 39/10
10a + 10ar + 10ar2 =39r … equation (3)
Substituting a = 1 in3 we get
10(1) + 10(1)r +10(1)r2 = 39r
10r2 –29r + 10 = 0
10r2 –25r – 4r + 10 = 0… equation (4)
5r(2r – 5) – 2(2r – 5)= 0
r = 2/5 or 5/2
so now the equationwill be,
1/(2/5), 1, 1×2/5 or1/(5/2), 1, 1×5/2
5/2, 1, 2/5 or 2/5, 1,5/2
∴ The threenumbers are 2/5, 1, 5/2