Question -
Answer -
Given:
(3x2┬атАУ1/x3)10
Let us consider the 7th┬аtermas T7
So,
T7┬а= T6+1
=┬а10C6┬а(3x2)10-6┬а(-1/x3)6
=┬а10C6┬а(3)4┬а(x)8┬а(1/x18)
= [10├Ч9├Ч8├Ч7├Ч81] /[4├Ч3├Ч2├Чx10]
= 17010 / x10
тИ┤ The 7th┬аtermof the expression (3x2┬атАУ 1/x3)10┬аis17010 / x10.