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Question -

How many different boat parties of 8, consisting of 5 boys and 3 girls, can be made from 25 boys and 10 girls?



Answer -

Given:

Total boys are = 25

Total girls are = 10

Boat party of 8 to bemade from 25 boys and 10 girls, by selecting 5 boys and 3 girls.

So,

By using the formula,

nCr = n!/r!(n – r)!

25C5 × 10C3 =25!/5!(25 – 5)! × 10!/3!(10-3)!

= 25! / (5! 20!) ×10!/(3! 7!)

=[25×24×23×22×21×20!]/(5! 20!) × [10×9×8×7!]/(7! 3!)

= [25×24×23×22×21]/5!× [10×9×8]/(3!)

=[25×24×23×22×21]/(5×4×3×2×1) × [10×9×8]/(3×2×1)

= 5×2×23×11×21 × 5×3×8

= 53130 × 120

= 6375600

 The total numberof different boat parties is 6375600 ways.

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