Question -
Answer -
Given the height offrustum cone = 12 cm
Radii of a frustumcone are 12 cm and 3 cm
So, r1 =12 cm; r2 = 3 cm
Let slant height ofthe frustum cone be ‘L’
Then, we know that
L = 15 cm
Now, the total surfacearea of frustum of a cone = π (r1 + r2) x L + π r12 +π r22
= π (12 + 3)15 +π122 + π32
Thus, total surfacearea of the frustum = 378 π cm2
Next,
Volume of frustum cone= 1/3 π(r22 + r12 +r1 r2 )h
= 1/3 π(122 +32 + 12 × 3) × 12 = 756π cm3
Therefore, the volumeof the frustum cone = 756 π cm3