Question -
Answer -
Given,
Perimeter of the upperend = 44 cm
2 ╧А r1┬а=44
2(22/7) r1┬а=44
r1┬а= 7cm
Perimeter of the lowerend = 33 cm
2 ╧А r2┬а=33
2(22/7) r2┬а=33
r2┬а=21/4 cm
Now,
Let the slant heightof the frustum of a right circular cone be L
L = 16.1 cm
So, the curved surfacearea of the frustum cone =┬а╧А(r1┬а+ r2)l
=┬а╧А(7 + 5.25)16.1
Curved surface area ofthe frustum cone = 619.65┬аcm3
Next,
The volume of thefrustum cone = 1/3 ╧А(r22┬а+ r12┬а+r1┬аr2┬а)h
= 1/3 ╧А(72┬а+5.252┬а+ (7) (5.25)┬а) x 16
= 1898.56┬аcm3
Thus, volume of thecone = 1898.56┬аcm3
Finally, the totalsurface area of the frustum cone
= ╧А(r1┬а+r2) x L + ╧А r12┬а+ ╧А r22
= ╧А(7 + 5.25) ├Ч 16.1 +╧А72┬а+ ╧А5.252
=┬а╧А(7 + 5.25) ├Ч16.1 + ╧А(72┬а+ 5.252)┬а= 860.27┬аcm2
Therefore, the totalsurface area of the frustum cone is 860.27┬аcm2