Question -
Answer -
Given,
Height of the bucket(h) = 24 cm
Radius of the circularends of the bucket 5 cm and 15 cm
So, r1 =5 cm; r2 = 15 cm
Let ‘L’ be the slantheight of the bucket
Then, we know that
Now,
Curved surface area ofthe bucket
= π(r1 +r2)l + πr12
= π(5 + 15)26 +π52 = π(520 + 25) = 545π cm2
Therefore, the curvedsurface area of the bucket = 545π cm2