Question -
Answer -
Given,
Height of frustum (h)= 8 m
Radii of the frustumcone are 13 cm and 7 cm
So, r1┬а=13 cm and r2┬а= 7┬аcm
Let тАШLтАЩ be slantheight of the frustum cone
Then, we know that
Curved surface area ofthe frustum┬а(s1) = ╧А(r1┬а+ r2) ├Ч L =┬а╧А(13 + 7) ├Ч 10┬а=┬а200 ╧А m2
Then, given slantheight of conical cap = 12 m
Base radius of uppercap cone = 7 m
So, the curved surfacearea of upper cap cone┬а(s2) = ╧Аrl┬а=┬а╧А ├Ч 7 ├Ч12┬а=┬а264┬аm2
Thus, the total canvasrequired for tent┬а(S) = s1┬а+ s2
S =┬а200╧А + 264 =892.57 m2
Therefore, the canvasrequired for the tent is 892.57 m2.