Question -
Answer -
Given,
A milk container ofthe form of frustum of a cone
The radius of thelower end (r1) = 8 cm
The radius of theupper end (r2) = 20 cm
Let h be its height, h= 16 cm
Then, the capacity ofthe container = Volume of frustum of the cone
= 1/3 ╧А(r22┬а+r12┬а+ r1┬аr2┬а)h
= 1/3 ╧А(202┬а+82┬а+ (20) (8)┬а) x 16
= 10459.42 cm3
= 10.46 litres
Now, given that costof 1 litre of milk = Rs 44
Then the cost of 10.46litres of milk = Rs (44 x 10.46) = Rs 460.24