Question -
Answer -
Given,
Height of theCylindrical portion (H) = 13 cm
Radius of theCylindrical portion (r) = 5 cm
Height of the wholesolid = 30 cm
Then,
The curved surfacearea of the cylinder (S1) = 2πrh
S1 =2π(5)(13)
S1 =408.2 cm2
Let, ‘L’ be the slantheight of the cone
And, the curvedsurface area of the cone (S2) = πrL
S2 =π(6)L
For conical part, wehave
h = 30 – 13 – 5 = 12cm
Then, we know that
L2 = r2 +h2
L2 = 52 +122
L2 =25 + 144
L2 =169
L = 13 m
So,
S2 =π(5)(13) cm2
S2 =204.28 cm2
Now, the curvedsurface area of the hemisphere (S3) = 2πr2
S3 =2π(5)2
S3 =157.14 cm2
Thus, the total curvedsurface area (S) = S1 + S2 + S3
S = (408.2 + 204.28 +157.14)
S = 769.62 cm2
Therefore, the surfacearea of the toy is 770 cm2