Given,
Radius of the commonbase (r) = 3.5 cm
Height of thecylindrical part (h) = 10 cm
Height of the conicalpart (H) = 6 cm
Let, ‘l’ be the slantheight of the cone
Then, we know that
l2 = r2 +H2
l2 =3.52 + 62 = 12.25 + 36 = 48.25
l = 6.95 cm
So, the curved surfacearea of the cone (S1) = πrl
S1 = π(3.5)(6.95)
S1 =76.38 cm2
And, the curvedsurface area of the hemisphere (S2) = 2πr2
S2 = 2π(3.5)2
S2 =77 cm2
Next, the curvedsurface area of the cylinder (S3) = 2πrh
S2 = 2π(3.5)(10)
S2 =220 cm2
Thus, the totalsurface area (S) = S1 + S2 + S3
S = 76. 38 + 77 + 220= 373.38 cm2
Therefore, the totalsurface area of the solid is 373.38 cm2