Question -
Answer -
Given,
Height/length of thecylindrical road roller = h = 1 m = 100 cm
Internal Diameter ofthe cylindrical road roller = 54 cm
So, the internalradius of the cylindrical road roller = 27 cm = r
Also given, thethickness of the road roller (T) = 9 cm
Let us assume that theouter radii of the cylindrical road roller be R.
T = R – r
9 = R – 27
R = 27 + 9
R = 36 cm
Now,
The volume of the ironsheet (V) = π × (R2 − r2) × h
V = π × (362 −272) × 100
V = 1780.38 cm3
Hence, the volume ofthe iron sheet = 1780.38 cm3
It’s given that, massof 1 cm3 of the iron sheet = 7.8 gm
So, the mass of1780.38 cm3 of the iron sheet = 1388696.4gm = 1388.7 kg
Therefore, the mass ofthe road roller is 1388.7 kg