Question -
Answer -
Given,
Internal diameter ofhollow spherical shell = 6 cm
So, the internalradius of hollow spherical shell = 6/2 = 3 cm = r
External diameter ofhollow spherical shell = 10 cm
So, the externaldiameter of hollow spherical shell = 10/2 = 5 cm = R
Diameter of thecylinder = 14 cm
So, the radius ofcylinder = 14/2 = 7 cm
Let the height ofcylinder be taken as h cm
Then, according to thequestion we have
Volume of cylinder =Volume of spherical shell
π × r2 ×h = 4/3 π × (R3 – r3)
π × 72 ×h = 4/3 π × (53 – 33)
h = 4/3 x 2
h = 8/3 cm
Therefore, the heightof the cylinder = 8/3 cm