Question -
Answer -
Given,
Internal diameter ofthe hollow sphere = 6 cm
So, the internalradius of the hollow sphere = 6/2 cm = 3 cm = r
External diameter ofthe hollow sphere = 10 cm
So, the externalradius of the hollow sphere = 10/2 cm = 5 cm = R
We know that,
Volume of the hollowspherical shell = 4/3 π × (R3 – r3)
= 4/3 π × (53 –33) ….. (i)
And given, the lengthof the solid cylinder = 8/3 cm
Let the radius of thesolid cylinder be r cm
We know that,
Volume of the cylinder= π × r2 × h
= π × r2 ×8/3 ….. (ii)
Now equating both (i)and (ii), we have
4/3 π × 53 –33 = π × r2 × 8/3
4/3 x (125 – 27) = r2 ×8/3
98/2 = r2
r2 =49
r = 7
So, d = 7 x 2 = 14 cm
Therefore, thediameter of the cylinder is 14 cm