Question -
Answer -
Given,
Diameter of the coin =1.75 cm
So, its radius =1.74/2 = 0.875 cm
Thickness or theheight = 2 mm = 0.2 cm
We know that,
Volume of the cylinder(V1) = πr2h
= π 0.8752 ×0.2
And, the volume of thecuboid (V2) = 11 × 10 × 7 cm3
Let the number ofcoins needed to be melted be n.
So, we have
V2 = V1 ×n
11 × 10 × 7 = π 0.8752 ×0.2 x n
11 × 10 × 7 = 22/7 x0.8752 × 0.2 x n
On solving we get, n =1600
Therefore, the numberof coins required are 1600