Question -
Answer -
Let the radius of thebig ball be x cm
The, the radius of thesmall ball = x/4 cm
And, let the number ofballs = n
Then according to thequestion, we have
Volume of n smallballs = Volume of the big ball
n x 4/3 π(x/4)3 =4/3 πx3
n x (x3/64) = x3
n = 64
Therefore, the numberof small balls = 64
Next,
Surface area of allsmall balls/ surface area of big ball = 64 x 4π(x/4)2/ 4π(x)2
= 64/16 = 4/1
Thus, the ratio of thesurface area of the small balls to that of the original ball is 4:1