Question -
Answer -
Given,
Internal diameter ofhollow sphere = 4 cm
So, the internalradius of hollow sphere = 2 cm
External diameter ofhollow sphere = 8 cm
So, the externalradius of hollow sphere = 4 cm
We know that,
Volume of the hollowsphere 4/3 π × (43 – 23) … (i)
Also given,
Diameter of the cone =8 cm
So, the radius of thecone = 4 cm
Let the height of thecone be x cm
Volume of the cone 1/3π × 42 ×h ….. (ii)
As the volume of thehollow sphere and cone are equal. We can equate equations (i) and (ii)
So, we get
4/3 π × (43 –23) = 1/3 π × 42 × h
4 x (64 – 8) = 16 x h
h = 14
Therefore, the heightof the cone so obtained will have a height of 14 cm