Question -
Answer -
Given,
Diameter of the copperwire = 1 cm
So, radius of thecopper wire = 1/2 cm = 0.5 cm
Length of the copperrod = 8 cm
We know that,
Volume of the cylinder= π r2h
= π × 0.52 ×8 ……. (i)
Length of the wire =18 m = 1800 cm
Volume of the wire = πr2h
= π r2 ×1800 ….. (ii)
On equating both theequations, we have
π × 0.52 ×8 = π r2 × 1800
r2 = 2/1800 = 1/900
r = 1/30 cm
Therefore, thediameter of the wire is 1/15 cm i.e. 0.67 mm which is the thickness of thewire.