Question -
Answer -
Let us assume probability of passing the English examinationis 0.75 be P(A).
And also assume the probability of passing the Hindiexamination is be P(B).
Here given, P(A) = 0.75, P(A∩B) – 0.5, P(AI∩BI)= 0.1
We know that, P(AI∩BI) = 1 – P(A∪B)
Then, P(A∪B) = 1 – P(AI∩BI)
= 1 – 0.1
= 0.9
∴ P(A∪B) = P(A) + P(B) – P(A∩B)
0.9 = 0.75 + P(B) – 0.5
Transposing 0.75, – 0.5 to LHS and it becomes – 0.75, 0.5.
P(B) = 0.9 + 0.5 – 0.75
= 0.65