The Total solution for NCERT class 6-12
From the question it is given that, P(A) = 0.42, P(B) = 0.48and P(A and B) = 0.16.
(i) P(not A) = 1 – P(A)
= 1 – 0.42
= 0.58
(ii) P(not B) = 1 – P(B)
= 1 – 0.48
= 0.52
(iii) P(A not B) = P(A ∪B) = P(A) + P(B) – P(A ∩ B)
= 0.42 + 0.48 – 0.16
= 0.74